A 0.63-kg soccer ball is lifted above the ground acquiring a potential energy of
ID: 1600458 • Letter: A
Question
A 0.63-kg soccer ball is lifted above the ground acquiring a potential energy of 28 joules. If the ball is dropped what is its velocity right before hitting the ground? (your answer must have two decimals and include IS units) What is the kinetic energy of a 65-g bullet leaving a rifle's muzzle at 280 m/s? (express, result with one decimal followed by simplified IS units) A wind turbine has a rated power of 859 kW. Assuming the turbine is operating at full power 42 % of the time, and shut down at all other times, find the total energy in MWh that the wind turbine can deliver in one year (365 days). (results with single decimal and no units). A new type of combustible gas has an energy intensity of 198, 015 Btu/gal. A 17-gallon fuel tank of a car is filled in about 4.7 minutes with the new invention. Estimate the rate of energy pumped into the gas tank during refueling in mega-watts? (zero decimals and include units) An 89-kg athlete can climb 60 steps in 30 seconds. Assuming the height of each step is 0.24 m, what is the average power output during the climb? (express result with no decimals followed by simplified IS units) Mary weighs 120 pounds. What is her weight in newtons? (express, result with one decimal followed by units) Peter's body mass is 215 pounds. What is his weight in newtons.? (express, result with one decimal followed by units) How much you should lower the jack handle to raise al, 691-lb car 2 cm if you weight only 228 pounds? (express, result with two decimals and including IS units) For a jack with a mechanical advantage of 2.5, how much displacement is required to raise a truck 33 cm?Explanation / Answer
1.
m = mass of ball = 0.63 kg
PE = potential energy = 28 Joules
v = velocity of ball just before hitting the ground
using conservation of energy
kinetic energy gained by ball = PE
(0.5) m v2 = PE
(0.5) (0.63) v2 = 28
v = 9.43 m/s
2.
m = mass = 65 g = 0.065 kg
v = speed = 280 m/s
Kinetic energy is given as
KE = (0.5) m v2 = (0.5) (0.065) (280)2 = 2548 J = 2.5 x 103 J
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