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Four resistors are connected to a battery with a terminal voltage of 12 V, as sh

ID: 1600722 • Letter: F

Question

Four resistors are connected to a battery with a terminal voltage of 12 V, as shown in the figure below, use the following variables as necessary: R_1 = 32.0 Ohm and R_2 =75.0 Ohm. (a) How would you reduce the circuit to an equivalent ingle resistor connected to the battery? Use this procedure to find the equivalent resistance of the circuit. (b) Find the current delivered by the battery to this equivalent resistance. (c) Determine the power delivered by the battery. (d) Determine the power delivered to the 50.0 Ohm resistor. The resistance between points a and b in the figure below drops to five sixths its original value when switch S is closed. Determine the value of R. Consider the series RC circuit shown below for which R = 45.0 k Ohm, C = 20 mu F, and epsilon = 9.0 V. Find the following.

Explanation / Answer

2)

Two at the top are in series and are equivalent to 82

that is in parallel with 75, equivalent to 82*75/(82+75) = 39

that in series with 20 is equivalent to 59

Total current is 12/59 = 0.203 amps

Voltage across the 39 is 39*0.203 = 7.93 volts

that causes a current into the 82 of 7.93/82 = 0.0967 amps.

And that causes power in the 50 of 0.0967^2*50 = 0.4678 watts

3)

Before closing the switch, resistance between a and b is

R + 100 II 100 = R + 50

After the switch is closed, it becomes

R + 2 x (90 II 10) = R + 18.

The statement specifies that this is 5/6 of the former figure, so

R + 18 = 5 /6(R + 50)

6R + 108 = 5R + 250

R = 250 - 108 = 142

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