A 400-kg piano slides 3.6 m down a 23 incline and is kept from accelerating by a

Question

A 400-kg piano slides 3.6 m down a 23 incline and is kept from accelerating by a man who is pushing back on it parallel to the incline.(Figure 1)

Part A

Determine the force exerted by the man.

Express your answer using two significant figures.

Part B

Determine the work done by the man on the piano.

Express your answer using two significant figures.

Part C

Determine the work done by the force of gravity.

Express your answer using two significant figures.

Part D

Determine the net work done on the piano. Ignore friction.

Express your answer using two significant figures.

Part C

Determine the work done by the force of gravity.

Express your answer using two significant figures.

Part D

Determine the net work done on the piano. Ignore friction.

Express your answer using two significant figures.

Explanation / Answer

Here ,

part A)

force exerted by the man = m * g * sin(theta)

force exerted by the man = 400 * 9.8 * sin(23)

force exerted by the man = 1531.67 N

part B)

work done on piano by the man = force * distance

work done on piano by the man = -1531.67 * 3.6

work done on piano by the man = -5513.99 J

part C)

work done by the force of gravity = - work done by man

work done by the force of gravity = 5513.99 J

part d)

net work done on the piano = change in kinetic energy

net work done on the piano = 0 J

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