Two identical light bulbs labeled A and B. are connected in series with a batter

Question

Two identical light bulbs labeled A and B. are connected in series with a battery and are illuminated equally. There is a switch in the circuit that is initially open. Which one of the following statements concerning the two bulbs is true after the switch is closed? Bulbs A and B win be off. Bulbs A and B win be equally illuminated. Bulb A will be brighter and bulb B will be off. Bulb A will fire off and bulb 3 will be brighter Bulb A will be off and bulb B will be the same brightness as before the switch was closed. Which of the following wires has the least resistance? (Assume all are made of the metal). Short. Wide & Hot Short. Wide & Cold Short. Skinny & Cold Long. Wide & Cold long. Skinny & Hot An empty parallel plate capacitor is to be redesigned by inserting a dielectric material such that the capacitance remains the same, but both the plate area and separation distances are halved. What must be the d electric constant of the material to achieve this? 1/4 1/2 2 4 No dielectric material is needed, the plates can remain empty. Four of values: 10 Ohm 20 Ohm 30 Ohm & 40 Ohm are to be in the given circuit such that the equivalent resistance of the circuit is equal to 76.7 Ohm. Which of the following accomplice this? R_1 = 30 Ohm. R_2 Ohm = 10 Ohm, R_1 = 20 Ohm, R_4 = 40 Ohm R_1 = 40 Ohm R_2 = 20 Ohm, R_1 = 10 Ohm, R_4 = 30 Ohm R_1 = 40 Ohm. R_2 = 10 Ohm, R_1 = 20 Ohm, R_4 = 30 Ohm All of the above produce the desired equivalent resistance. None of the above produce the desired equivalent resistance. A circuit consists of a 10 Cl resistor connected to a 12-volt battery. If the current through the resistor is 1.18 amps, what can be said of the battery? It is an ideal battery with an internal resistance of zero It is a real battery with an internal resistance of zero It is an ideal battery with internal resistance 0.17 Ohm It is a real battery with internal: resistance of 0.17 Ohm It depends on if the resistor is connected to the battery in series or parallel.

Explanation / Answer

from ohms law

for ideal battery

I = V/R

I = 12/10 = 1.2 A

given current 1.18 < I

it is a real battery

for real battery

i = V/(R+r)

1.18 = 12/(10+r)

r = 0.17 ohm

It is a real battery with internal resistance 0.17 ohm

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.