If a particle travels a distance of 1 meter before reaching the window, in a tim

Question

If a particle travels a distance of 1 meter before reaching the window, in a time duration of 10 sec, and if the mass of the particle is 1 micro-gram and the charge on the particle is 10^-12 Coulomb, then the magnitude of the electric field intensity is A) 3 Newton/Coulomb. B) 146 Newton/Coulomb. C) 20 Newton/Coulomb. In the problem described above, the surface charge density on the window is equal to A) 1.4 times 10^-12 Coulomb/m^2. B) 3.5 times 10^-10 Coulomb/m^2. C) 5.6 times 10^-14 Coulomb/m^2.

Explanation / Answer

1. Assume The initial velocity of the charged particle is u=0 m/s

so s = 0.5 x a x t2

a = 2s/t2 = 2 x 1/100 = 2 x 10-2 m/s2

force = ma

qE = ma

E = ma/q = 10-9 x 2 x 10-2/ 10-12 = 20 Newtons/ Coulomb

Hence The electric field is 20 Newtons/ Coulomb (Option C)

Question 9

electric field E = /2

= 2 E = 2 x 8.85 x 10-12 x 20 = 3.5 x 10-10 Coulombs/m2

Hence the option B is correct that is the charge density is 3.5 x 10-10 Coulombs/m2

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