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s Print Calculator Periodic Table Question 11 of 12 sapungLearning Abeam of init

ID: 1602315 • Letter: S

Question

s Print Calculator Periodic Table Question 11 of 12 sapungLearning Abeam of initially unpolarized light passes through a sequence of three ideal polarizers. The between the axes of the first and second polarizers is 19.1. and the angle between the axes of the second and third polarizers is 56.1.What is the ratio of the intensity of light emerging from the third polarizer, b, to the intensity otlight incident on the first polarizer, lo? 19.10 0.381 56.1e There is hint availablel Previous check Answer o Next a Ext O e O He

Explanation / Answer

when light passes through a polarizer ,the intensity is cut in half,therefore the transmitted intensity is Io/2

then I1 = Io/2 = 0.5*Io

using the malus law

I2 = I1*cos^2(theta)

I2 = 0.5Io*cos^2(19.1)

I2 = 0.446*Io


when it was going into third polarizer

I3 = I2*cos^2(56.1)

I3 = 0.446*Io*cos^2(56.1)

I3 = 0.138*Io

I3/Io = 0.138