Hooke\'s Law Physics Lab Questions Pre Lab B-16 Hooke\'s Law Read manual H-16 th
ID: 1602895 • Letter: H
Question
Hooke's Law Physics Lab Questions
Explanation / Answer
here,
mass of object, m = 100 g = 0.1 kg
stretched distance, x = 20 cm = 0.2 m
from hooke's law,
spring force = spring constant * stretched distance
F = k * x
Part D :
from newton law of motion : SUM(F) = 0
spring force = force due to gravity
kx = mg
spring constant, k = mg/x
spring constant, k = 0.1 * 9.81 / 0.2
spring constant, k = 4.905 N
Part a :
Spring force, F1 = k*x
spring force, F1 = 4.905 * 0.2
spring force, F1 = 0.987 N
Part B :
Spring force, F2 = k*x
spring force, F2 = 4.905 * 0.3
spring force, F2 = 1.472 N
additional force , F = F2 - F1
additional force , F = 1.472 - 0.987
additional force , F = 0.485 N
part C :
additional stretch, x = f/k = 0.485 / 4.905
additional stretch, x = 0.09887 m = 9.88 cm
for rest of parts repost it again.
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