3) A ball is thrown upward with an tial velocity m/s at an angle of 60.0° above

Question

3) A ball is thrown upward with an tial velocity m/s at an angle of 60.0° above the ini of 20 horizontal. Use energy to find the ball's height above the ground (5 pb) the block can slide 3 ramps howe The ball has 10 J or ponentialenerge the top of the ramps. The ramps are 2,4 and 6 meters long Ognore aitresitaancs fristian) ramp? If it slides down the shonest how much kinetic energy will have the bonom of the at ramp, point) b) 2.5 01. ne ball will be going the fastest if it rolls down which ramp? point) a) The ball will have the same speed no matter which ramp. b) A c) B d) C

Explanation / Answer

Using Energy conservation in y-direction:

KEi + PEi = KEf + PEf

Viy = V0*sin A

Vfy = 0,since at max height velocity is zero in vertical direction

KEi = 0.5*m*(V0*sin A)^2

KEf = 0

PEi = 0, since h = 0

PEf = m*g*hmax

Now

0.5*m*V0^2*(sinA)^2 = m*g*hmax

hmax = 0.5*20*20*(sin 60)^2/9.81

hmax = 0.5*400*3/(4*9.81) = 15.29 m

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