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A) A thin diverging lens of focal length 28 cm is placed 11 cm to the right of a

ID: 1603638 • Letter: A

Question

A) A thin diverging lens of focal length 28 cm is placed 11 cm to the right of a point source of blue light on the axis of the lens. Where is the image of the source? (Take the origin to be at the lens and the positive direction to be to the right.)

B) A thin converging lens of focal length 19 cm is located at the origin and its axis lies on the x axis. A point source of red light is placed at location <13, 2, 0> cm Where is the location of the image of the source? (Express your answer in vector form.)

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Explanation / Answer

A)

lens equation 1/u + 1/v = 1/f

ingaedistance

1/v = 1/f-1/u

v = uf/u-f = 28*11/(11-28) = -18.11 cm

B)

lens equation 1/u + 1/v = 1/f

ingaedistance

1/v = 1/f-1/u

v = uf/u-f = 19* r /(r-19)

where r is the vector form of object position

the vector form of image position v = 19*(13, 2, 0) / [(13, 2, 0) -( 19,0,0)]

                                                         = (-247, 38,0)/(-5.847) = (42.24,-6.499,0)

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