You take a strand of copper wire and form it into a circular loop of circumferen

Question

You take a strand of copper wire and form it into a circular loop of circumference of 0.355 m. You then place the loop in a uniform, constant magnetic field of magnitude 0.00213 T that is oriented perpendicular to the face of the loop. Pulling on the ends of the wire, you reduce the circumference of the loop to 0.117 m in a time interval of 0.822 s. Assuming the loop remains circular as it shrinks, what is the magnitude of the average emf epsilon induced around the loop during this time interval?

Explanation / Answer

emf = BdA/dt

A1 = 3.14*0.0565^2 = 0.01 m^2

A2 = 3.14*0.0186^2 = 0.001 m^2

emf = 0.00213*(0.01-0.001)/0.822 = 2.33*10^-5 V

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