A hammer strikes one end of a thick iron rail of length 8.69 m. A microphone loc

Question

A hammer strikes one end of a thick iron rail of length 8.69 m. A microphone located at the opposite end of the rail detects two pulses of sound, one that travels through the air and a longitudinal wave that travels through the rail. (The speeds of sound in air and in iron are 343 m/s and 5950 m/s, respectively. (a) Which pulse reaches the microphone first? the pulse traveling through the iron rail the pulse traveling through the air (b) Find the separation in time between the arrivals of the two pulses. Need Help? Tak to a Tutor O -1 points oscolPhyst 16.P051.WA My Notes Ask Your Teach What is the wave of the waves you create in a swimming pool if you splash your hand at a rate of 6.6 Hz and the waves propagate at 0.75 m/s? length

Explanation / Answer

a) time taken by the pulse in air is t1 = d/v1 = 8.69/343 = 0.02533 sec

time taken by the pulse in rail is t2 = d/v2 = 8.69/5950 = 0.00146 sec

So the pulse travelling with greater speed reaches the microphone first

b) sepeartion in time is t1-t2 = 0.02533-0.00146 = 0.02387 sec

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v = lamda*f

lamda = v/f = 0.75/6.6 =0.113 m

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v = lamda*f

since speed of sound is constant fro two waves in air

lamda1*f1 = lamda2*f2

f2 = lamda1*f1/lamda2 = (lamda*f)/(lamda/2) = 2*f

so the answer is 2f

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