we we Mo The Hayden C Dropbox, Inc (US) https://www. dropbox.com/home/phys%20209
ID: 1604921 • Letter: W
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we we Mo The Hayden C Dropbox, Inc (US) https://www. dropbox.com/home/phys%20209%20t2?preview 20170408 151735 jpg EE: Apps Q ART 100 Exam 2 Flash w art WebAssign LOG IN PAWS E oo LL Boas and Anacondas Vertical Motion Phy YouTube N Netflix Moodle e Books Home Dropbox Ask Your Teacher My Notes namal and Davo are lifting a large chest, weightng 210 lb by using Lope handles attached to either side As they lift and hold it up so that it is motionless, each handle makes a different angle with the two is 25.0o and the angle between Dayo's handle and the vertical side of the chest is respect to the vertical side of the chest (see figure below). f the Angle betweun lama's handle and the vertical side answers submitted in WebAssign.) 30 oo, what are the tensions in each twandle? (Due to the nature ol this problem, do noi use rounded inte mediate values in your caloulalions includi Teacher My Notes Ask Your Find the dol product the following vectors. 6.50i 4 2.11 3.13k and B 551 13.801 My Notes o Ask Your Te 24 of 25 31% GA 0 kg) rides his skateboar d at a local skatu park. He start w and begins a descent down the track, always main contact with the surface the mass of the skateboar uligible, as Is ction except where no d 6:16 PM 4/8/2017Explanation / Answer
As the box is in equilibrium, net force and net torque acting on it must be zero.
Apply, Fnetx = 0
FTJ*cos(25) - FTD*cos(30) = 0
FTD = FTJ*cos(25)/cos(30)
FTD = 1.0465*FTJ ---------(1)
now apply, Fnety = 0
FTJ*sin(25) + FTD*sin(30) - W = 0
FTJ*sin(25) + FTJ*1.0465*sin(30) = W
FTJ = W/(sin(25) + 1.0465*sin(30) )
= 210/( sin(25) + 1.0465*sin(30) )
= 222 lb
= 222*4.448
= 987 N <<<<<<<<<--------------Answer
from equation 1
FTD = 1.0465*FTJ
= 1.0465*222
= 232 lb
= 232*4.448
= 1032 N <<<<<<<<<--------------Answer
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