Light shines on a diffraction grating with 9600 lines/cm. The first-order maximu

Question

Light shines on a diffraction grating with 9600 lines/cm. The first-order maximum occurs at an angle of 33 degree. What is the wavelength of the light? A) 452 nm B) 513 mm C) 567 nm D) 683 nm E) 865 nm A person is nearsighted (myopic) and without glasses the furthest distance that she can see an object clearly is 66.7 cm. You would prescribe contact lenses with a power of: A) 1.45 diopters B) -1.45 diopters C) 1.50 diopters D) -1.50 diopters E) 1.55 diopters An inkjet color printer uses tiny dots of red (lambda = 660 nm), green (lambda = 550 nm) and blue (lambda = 479 nm) ink to produce an image. At normal viewing distances, the eye cannot resolve these dots. You thus see a "smooth" picture. What is the maximum acceptable dot spacing so that a person (with pupil diameter 2.0 mm and index of refraction for the eye of 1.33) can just resolve the individual green dots if the paper is held 25 cm from the eye? A) 33 mu m B) 49 mu m C) 63 mu m D) 83 mu m E) 96 mu m A vertically polarized light wave has an intensity of 80 W/m^2. This wave is directed towards three ideal polarizers. Polarizer A has its transmission axis at an angle of theta = 45 degree with the vertical; polarizer B has its axis at an angle of theta_2 = 90 degree with the vertical; and polarizer C has its axis at an angle of theta_2 = 45 degree with the vertical. What is the intensity of the light coming out of polarizer C? A) 0 B) 5 W/m^2 C) 10 W/m^2 D) 20 W/m^2 E) 28.5 W/m^2

Explanation / Answer

8. distance d = 1/N

= 1/9600 lines/cm

= 1.0416*10^-6 m

condition for constructive interference

d*sintheta = m*lambda

(1.0416*10^-6)*sin(33) = (1)*lambda

lambda = 567 nm

option (c) is correct answer

9. from lens equation

1/f = 1/d0 + 1/di

p = 1/f = 1/0.667 + 1/infinity

= 1.50 dipoters

option (c) is correct answer

as per guide lines i did first two problems

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