An ice skater is executing a figure eight, consisting of two identical shaped ci
ID: 1606951 • Letter: A
Question
An ice skater is executing a figure eight, consisting of two identical shaped circular tangent circular paths. Throughout the first loop she increases her speed uniformly, and during the second loop she moves at constant speed. What can you say about the acceleration on the first loop? (a) The angular acceleration is zero (b) The tangential acceleration is zero but the centripetal acceleration is not zero (c) The centripetal acceleration and the tangential acceleration are not zero. A boy and a girl are riding on a merry-go-round which is turning at a constant rate. The boy is near the outer edge, and the girl is closer to the center. Who has the greater linear speed?, A) the boy, B) the girl, C) Both have the same non-zero linear velocity., D) Both have zero linear velocity. A baseball arrives at home plate at a speed of 43.3 m/s. The batter hits the ball along the same line straight back to the pitcher at 68.4 m/s. The baseball has a mass of 0.145 kg and the bat is in contact with the ball for 6.28 times 10^-4 s. (a) What the impulse that the bat gave to the ball, (b) What is the magnitude of the average force on the ball from the bat?Explanation / Answer
1.a) In the first loop she icnreases her speed v uniformly.
So tanggential accelration a = dv/dt
Now, = a/r, where is the angular acceleration and r is the radius of the loop
So the angular accelration is = a/r and not zero.
So statement (a) is false.
1.(b) As we saw above, tanggential accelration a = dv/dt.
So a will be zero only when the speed v is uniform which is not the case here as the speed is increasing.
So, tanggential accelration a will have a non zero value.
The centripetal accelration is = v2/r, so this is not zero.
1.(c) As we saw in (b) above the cennripetal acceleration and tangential acceleration are not zero.
So the statement (c) is true.
This concludes the answers. Check the answer and let me know if it's correct. If you need anymore clarification I will be happy to oblige.....
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