2-A 0.24-kg stone is held 1.5 m above the top edge of a water well and then drop

Question

2-A 0.24-kg stone is held 1.5 m above the top edge of a water well and then dropped into it. The well has a depth of 5.2 m.

(a) Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone–Earth system before the stone is released?

J

(b) Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone–Earth system when it reaches the bottom of the well?

J

(c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well?
J

Explanation / Answer

a)

PEi = m*g*hi = 0.24*9.8*1.5 = 3.53 J

b)

PEf= m*g*hf= 0.24*9.8*-5.2 = -12.23 J

c)

PE = PEf – PEi = -12.23 - 3.53 = - 15.76 J

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