The cube shown in the figure (Figure 1) 45.0 cm on a side, is in a uniform magne

Question

The cube shown in the figure (Figure 1) 45.0 cm on a side, is in a uniform magnetic field of B = 0.111 T , directed along the positive y-axis. Wires A, C, and D move in the directions indicated, each with a speed of 0.340 m/s . (Wire A moves parallel to the xy-plane, C moves at an angle of 45.0 below the xy-plane, and D moves parallel to the xz-plane.)

Part A.) What is the potential difference between the ends of wire A?

Part B.) What is the potential difference between the ends of wire C?

Part C.) What is the potential difference between the ends of wire D?

Thank you for your help. It is very much appreciated.

Explanation / Answer

Length of the rods A and C is l = length of the side of the cube = 45cm = 0.45m

Lenght of the rod D is L = 2(45cm) = 2(0.45m) (as the length of this rod is equal to diagonal of the face of the cube)

Part A.) A moves parallel to the xy-plane. It's velocity is parallel to the direction of B. So no emf will be induced across its ends. So potential difference across the ends of A is zero.

Part B.) The component of velocity of rod perpendicular to the field is v0 = vcos450 = (0.340 m/s) = 0.24m/s

So potential diffrence = Blv0 = (0.111T)(0.45m)(0.24m/s) = 0.012V

Part C.) here, component of velocity of the rod perpendicular to the length of the rod is v1 = vcos450, because the angle between the length of the rod and its velocity is 450

So potential difference across the rod D is E = BLv1 = BLvcos450 = (0.111T)(2(0.45m)) (vcos450)

or E = (0.111T)(0.45m)v = (0.111T)(0.45m)(0.34m/s) = 0.01689Volt

This concludes the answers. Check the answer and let me know if it's correct. If you need anymore clarification I will be happy to oblige....

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.