(a) Calculate the equivalent resistance of the R 1 and 5.00- resistors connected

Question

(a) Calculate the equivalent resistance of the R1 and 5.00- resistors connected in parallel.


(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00- and 4.00- resistors.


(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00- resistor.


(d) Combine the equivalent resistance found in part (c) with the R2 resistor.


(e) Calculate the total current in the circuit.
A

(f) What is the voltage drop across the R2 resistor?
V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00- resistor.
V

(h) Calculate the current in the 3.00- resistor.
A

Explanation / Answer

Given data

   R1 = 11.5 ohm , R2 = 2.3 ohm , V = 7.30 V

a) R1 and 5.00- resistors connected in parallel so the equivalent resistance is

   1/Ra = 1/R1+1/5

   1/Ra = 1/11.5+1/5

   Ra = 3.485 ohm

b) Ra and 4.00- resistors are in series then equivalen resistance is

   Rb = Ra+ 4 = 3.485 +4 = 7.485 ohm

c)equivalent resistance of the combined resistance of Rb and the parallel 3.00- resistor

   Rb and 3 ohm resistors are in parallel then

   1/Rc= 1/Rb + 1/3

   = 1/7.485 +1/3

   Rc = 2.142 ohm

d) now Rc and R2 are in series then the equivalent resistance is

   R = Rc+R2

   R = 2.142 +2.3 = 4.442 ohm

e) total current in the circuit is V = I*R

       I = v/R = 7.30/4.442 A

       I = 16.434 A

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