Table 2: Converging Mirror Measured Calculated Object distance o (cm) Image dist
ID: 1608526 • Letter: T
Question
Table 2: Converging Mirror
Measured
Calculated
Object distance o (cm)
Image distance I (cm)
Object Distance(1/o)
Image Distance (1/i)
10
no image
0.1
#VALUE!
20
no image
0.05
#VALUE!
30
no image
0.033333333
#VALUE!
40
27
0.025
0.037037037
50
24
0.02
0.041666667
60
23
0.016666667
0.043478261
70
21
0.014285714
0.047619048
80
20.5
0.0125
0.048780488
1. Determine the focal length of the mirror. Show all relevant equation and calculations.
2. Were the images upright or inverted? Was this the case for all trials?
3. Under what conditions (object distance) was the image larger? Under what conditions was the image smaller?
4. Were there object distances for which an image could not be located?
5. What is different, or significant, about this distance as compared to your measured focal length?
6. Where does the object have to be for a real image to form?
Measured
Calculated
Object distance o (cm)
Image distance I (cm)
Object Distance(1/o)
Image Distance (1/i)
10
no image
0.1
#VALUE!
20
no image
0.05
#VALUE!
30
no image
0.033333333
#VALUE!
40
27
0.025
0.037037037
50
24
0.02
0.041666667
60
23
0.016666667
0.043478261
70
21
0.014285714
0.047619048
80
20.5
0.0125
0.048780488
Explanation / Answer
1) Using mirror formula
1/di + 1/ do = 1/ f
Using object's distance 40cm and corresponding values
we get f = 16.12 cm
2) inverted for all trials
3) when do < 2f image is large
when do > 2f image is small
4) yes
5) do < f
6) do>= f
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