Consider a fission reaction where a Uranium-235 nucleus absorbs a neutron and th

Question

Consider a fission reaction where a Uranium-235 nucleus absorbs a neutron and then splits to Strontium, Xenon, and some neutrons. If the strontium nucleus has a mass number of 91 and the Xenon nucleus has a mass number of 142. How much energy is released in a single reaction? Use the attached table for the atomic masses of the nuclei. Give your answer in MeV and with 4 significant figures please. :) (Hint: Balance the reaction first).

Isotope Masses for Fission A | Atomic mass (u) Neutron 1.008665 235 | 235.043923 Uranium Strontium 38 87 86.908877 88 87.905612 89 88.907451 90 89.907738 91 90910203 92 91.91 1038 93 92.914026 94 93.91 5361 95 94.91 9359 96 95.921697 97 96.926153 98 97.928453 99 98.933240 Xenon 54 133 132.905910 134 | 133.905395 135 134.907227 136 135.907219 137 136.911 562 138 137.913950 139 138.918793 140 139.921640 141 140.926650 142 141.929710 143 142.935110 144 143.938510 145 144.944070 146-1- 145.947750 7218386197330 17 7153032659554 5577138169584 0000111112223 00001112223344 99999999999999 9999999999999 678901 333334444 28888999999999 7890123456789 33333334444 8889999999999 11111111111111 z0-92-38 28

Explanation / Answer

235U92 + 1n => 91 St 38 + 142 Xn 54 + 2n

on left side.

total mass, m1 = (235.043923) + (1.008665) =236.052588 u

on right side,

m2 =(90.910203) + (141.926650) + 2(1.008665) = 234.854183u

mass difference = m1 - m2 = 1.1984u

Energy released = 1.1984 x 931.5 = 1116.31 MeV

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