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An aluminum block measures 1.100 cm by 2.250 cm by 3.250 cm . Find its volume af

ID: 1609651 • Letter: A

Question

An aluminum block measures 1.100 cm by 2.250 cm by 3.250 cm . Find its volume after a 150 C temperature increase in two ways. Part A Find its volume after a 150 C temperature increase using aluminum's linear expansion coefficient on each side and then determining the new volume.
Part B Find its volume after a 150 C temperature increase using the volume expansion coefficient. An aluminum block measures 1.100 cm by 2.250 cm by 3.250 cm . Find its volume after a 150 C temperature increase in two ways. Part A Find its volume after a 150 C temperature increase using aluminum's linear expansion coefficient on each side and then determining the new volume.
Part B Find its volume after a 150 C temperature increase using the volume expansion coefficient. An aluminum block measures 1.100 cm by 2.250 cm by 3.250 cm . Find its volume after a 150 C temperature increase in two ways. Part A Find its volume after a 150 C temperature increase using aluminum's linear expansion coefficient on each side and then determining the new volume.
Part B Find its volume after a 150 C temperature increase using the volume expansion coefficient.

Explanation / Answer

l = l0(1+alpha*change in temperature)

l = 1.1(1+23*10^-6*150) = 1.104 cm

b = 2.250(1+23*10^-6*150) = 2.258 cm

h = 3.25*(1+23*10^-6*150) = 3.26 cm

v = lbh = 8.127 cm^3

v = v0(1+gama*change in temperature)

v = 1.1*2.25*3.25(1+69*10^-6*150) = 8.127 cm^3

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