A wire of length 0.65 m is conducting a current of I = 6.7 A in the +x direction

Question

A wire of length 0.65 m is conducting a current of I = 6.7 A in the +x direction through a B = 4.-T uniform magnetic field that is directed parallel to the wire in the -x direction. What are the magnitude and direction of the magnetic force on the wire? +x -x +y -y +z -z none of the above The magnetic field changes, so that now the force on the wire is F = 7.0 N in the +y direction. What are the magnitude and direction of the magnetic field now? (Assume that the magnetic field B is perpendicular to 1.)

Explanation / Answer

1) magnetic force acting on the wire,

F = B*I*L*sin(theta)

= B*I*L*sin(180)

= 0

direction : None of the above

2)

use, F = B*I*L*sin(theta)

B = F/(I*L*sin(theta))

= 7/(6.7*0.65*sin(90))

= 1.607 T

direction : -z

using right hand rule the direction of B can be determined.

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