Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

D wagwork csu MTH l yul (4) x Facebook Wiley Lus C secure l https edugenwi eyplu

ID: 1611235 • Letter: D

Question

D wagwork csu MTH l yul (4) x Facebook Wiley Lus C secure l https edugenwi eyplus.com/edugen/student/mainfr. Wiley PLUS Halliday, Fundamentals of Physics, 10e ty Phy versity Physi Home Read, study a Practice A Gradebook Assignment Open Assignment Chapter 16, Prob 052 A nope, under a tension of 113 N d fixed at both ends, oscillates in a second-harmonic standing wave pattem. The displacement of the rope is given by y 0,371m J3,00, 0)sin(10.0T where X-0 a one end of the rope x is in metera, and t isin seconds. What are (a) the longth of tho rope, (b) the speed of the waves on the rope, and (c) tho ma ofthoropo? (d) It the rope oscillates in athird-harmonic Review Results by study standing wave pattern, what will be the period of oscillation? (a) Number (b) Number Units m/s units kg (c) Number (d) Number Units s Click if you would like to Show Work for this question LINK TO SAMPLE PROeLEM LINC ToSAMPLEPROeLEM vIDEo MINI-LECTURE Question Attempts: Unlimited SAVEROR LATER All Rights Reserved. A Division of 4.22.3.4 807 PM Ask me anything

Explanation / Answer

F = 113 N
y = 0.371* (sin((*x)/3.00)) * sin( 10 *t)

comparing with
y = 2A sin (k*x) * sin ( * t)

a) in a second-harmonic, the wave length = the length of the rope
k = 2/ = /3.00 --> = 6 m
The length of the rope L = 6 m

b) The sped of the waves
v = /k = 10/(/3) = 30 m/s

c) melde's law :
v = (F *L/m)
--> m = F * L/v^2
=113 * 6/(30)^2
m= 0.753 kg

d)in a third-harmonic :
L = 1.5 ---> = 6/1.5 = 4m ( since1.5= 3/2)
v = /T --> T = /v = (4)/30 = 0.133 s