An air-filled parallel-plate capacitor is connected to a battery and allowed to

Question

An air-filled parallel-plate capacitor is connected to a battery and allowed to up. Now a slab of dielectric material is placed between the plates of the capacitor while the capacitor is still connected to the battery. Which is correct? a) The voltage across the capacitor had increased. b) The charge on the capacitor had increased. c) The energy stored in the capacitor had decreased. d) The charge on the capacitor had not changed. e) None of the above. The electric field lines (solid) and the equipotential lines (dashed) in a certain region of space are as shown below. Answer questions 13 and 14. When a positive charge is moved from point A to point D, the work done by the electric field is a) greater than the work done by the field when the same charge is moved from point point C b) equal to the work done by the field when the same charge is moved from point B to point C c) less than the work done by the field when the same charge is moved from point B point C The electric potential at C is a) greater than the electric potential at B b) equal to the electric potential at B c) less than the electric potential at B d) equal zero.

Explanation / Answer

when dielectric placed then c' = kc and v' = v/k

energy u' = 1/2kc*v^2/k^2 = u/k

energy decreased by k times

13) option a

because on equi potential line work done is zero

14) equal to B

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