The fact that an increase of pressure on an enclosed fluid is transmitted unifor

Question

The fact that an increase of pressure on an enclosed fluid is transmitted uniformly throughout the fluid is Law. A hydraulic jack is used to lift a load of weight 1000 N. The load-bearing cylinder has a radius of 4 cm, and the other piston has a radius of 1 cm. What force must be exerted on the smaller piston to support the load? 62.5 N 125 N 250 N 1000 N 4000 N Show calculation: If the atmospheric pressure is 1.1 times 10^5 Pa, the corresponding downward force on the top of a horizontal square area cm on each side is approximately 40 N 400 N 4000 N 10^5 N Show calculation A gas initially is at a pressure of 100 kPa. If its volume is halved while the absolute temperature is kept constant the new pressure will be _____ kPa. Explain your answer by using the appropriate law (formula): A gas originally occupies a volume of 0.5 m^3 at a pressure of 100 kPa. It is slowly allowed to expand until the volume is 2.5 m^3. Assuming the temperature is kept constant, the final pressure will be: 10 kPa 20 kPa 50 kPa 100 kPa 500 kPa Show calculation: It is observed that as bubbles rise in a deep column of water, the diameter of the bubbles increases. This is best explained by Bernoulli's Principle. Archimedes Principle. Boyle's Law. Pascal's Principle Show reasoning: Archimedes Principle states that the pressure in a fluid is directly related to the depth below the surface of the fluid. an object immersed in a fluid is buoyed up by a force to the weight of the displaced fluid. the pressure of a fluid is inversely proportional to the temperature of the fluid. the velocity of a fluid is directly proportional to the pressure exerted on the fluid. A hot air balloon derives its lift from the property of fluids as stated by Bernoulli's Principle. Archimedes Principle. Boyle's Law. Pascal's Principle. Explain what happens with the hot air balloon:

Explanation / Answer

1) pascal's

2) As pressure on both jacks to be same

F1/A1 = F2/A2

Fs/(*12) = 1000/(*42)

Fs = 62.5 N

3) force F = P*A

F=1.1*105 * (6*10-2)2 = 396N = 400N

4)

as P*V = constant

Pfinal * Vfinal = Pini * Vini

Pfinal * V/2 = 100 * V

Pfinal = 200 Kpa

5)

Here , Using Boyle's law

as P*V = constant

Pfinal * Vfinal = Pini * Vini

0.5 * 100 = Pfinal * 2.5

Pfinal = 20 KPa

the final pressure s 20 Kpa

6) Boyle's law

7) an object immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid.

8) Archimedes principle

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