Find the difference of the initial and the final masses for the 23992U23892U+n.

Question

Find the difference of the initial and the final masses for the 23992U23892U+n. The atomic mass of 23992U is 239.05429 u , the atomic mass of 23892U is 238.05078 u , the mass of neutron is 1.008665 u.

m =

Find the difference of the initial and the final masses for the 147N137N+n. The atomic mass of 147N is 14.003074 u, the atomic mass of 137N is 13.005739 u.

m =

Find the difference of the initial and the final masses for the 4019K3919K+n. The atomic mass of 4019K is 39.963999 u, the atomic mass of 3919K is 38.963707 u.

m =

Explanation / Answer

(a) Dm = (mU239 - mU238 - mn)

Dm = (239.05429 - 238.05078 -1.008665)u

Dm = -0.005155 u

1uc^2 =931.5 MeV

Dm =(-0.005155)*931.5 = -4.802 MeV/c^2

(b)Dm = (mN14 -mN13 -mn)

Dm = (14.003074 -13.005739 -1.008665)u

Dm = -0.01133 u

Dm =(-0.001133)*931.5 = -1.0554 MeV/c^2
Dm = (mK40 -mK39 -n)

Dm = (39.963999 -38.963707 -1.008665)u

Dm = -0.008373 u

Dm = (-0.008373)*931.5

Dm = -7.8 MeV/c^2

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