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201-01 Intro Physics 1-Ea 5 -04/10/2017 xam so kg is ame & HUID Each spring has

ID: 1612645 • Letter: 2

Question

201-01 Intro Physics 1-Ea 5 -04/10/2017 xam so kg is ame & HUID Each spring has a spring attached a double spring. constant to 000 Nm. o pts) What of the resulting spring constant for both springs combined? 50 coil (b) I10 ptsl How far are the springs stretched when the crate is attached and in balanced position (c) I10 ptsl When the crate is displaced from the balanced position by 20 cm and let go, it will oscillane ap and down. Calculate the time Tfor one full period of oscillation (T 1 m). (d) IBONUS 15 ptsl How much longer or shorter is the period of oscillation compared to above situation using a crate with twice the mass (100 kg)? (iij displacing the crate initially twice as far (40 cm)? one of the two springs (iii using only Page 3/4

Explanation / Answer

Ans 4) Ice Skater
the physice principle involved is conservation of angular momentum. the ice skater starts with an initial twist ,i.e.
with an initial angular momentum. as she starts spinning, she brings her arms closer to her body (rotation axis) which reduces the rotational inertia. since the angular momentum must remain constant, the angular speed increases accordingly. this is how an increase in angular speed is achieved.

Ans 5)
if we consider each mark on the scale to be 1m,
then for
Fig 1, net torque= 3m
fig 2, net torque= 3m
fig 3, net torque= 2m
fig 4, net torque=4m
so, fig 3, has smallest net torque.


Ans 8)
Given, frquency on earth, f= 1Hz
g(earth)= 9.81m/s^2
g(mars)=3.71 m/s^2

now, 1/f= T= 2 {sqrt (L/g)}
if f2= frqeuncy at mars, then
f2= (g(mars)/ g(earth)) * f =

thus, f2= 0.615 Hz