Two identical positive charge q are placed as shown in the right figure. Point P
ID: 1612742 • Letter: T
Question
Two identical positive charge q are placed as shown in the right figure. Point P is equidistant from both charges. At point P: A) The electric field points upward (+y). B) The electric field is zero (C) The potential (relative to infinity) is zero (D) The potential (relative to the infinity) points upward (+y) Three resistors (10 Ohm, 10 Ohm and 15 Ohm) are connected together as shown in the right figure. What is the equivalent resistance of this resistor network? (A) R_eq = 35 Ohm (B) R_eq = 20 Ohm (C) R_eq = 16 Ohm (D) R_eq = 17 Ohm (E) R_eq = 5 Ohm A conducting bar ab is moving on a metal rails in a uniform magnetic field B, which direction is into the page. Which of the following statements is correct? (A) induced current direction is from a to b and the induced force direction is to the left (B) induced current direction is from a to b and the induced force direction is to the right C) induced current direction is from b to a and the induced force direction is to the left (D) induced current direction is from b to a and the induced force direction is to the rightExplanation / Answer
2.
for series
Req = R1 + R2 + R3 + ....
for parallel circuit
1/Req = 1/R1 + 1/R2 + 1/R3 + .....
Initially 15 and 10 ohm are in parallel, so
1/Rp = 1/15 + 1/10
Rp = 6 ohm
Now 6 ohm and 10 are in series, so
Req = 6 + 10 = 16 ohm
Correct option is C.
1.
we know that electric field due to positive charge is directed away from from the charge.
electric field due to left charge will be directed at 45 deg from point P w.r.t to +x axis, and similarly
electric field due to right charge will be directed at 45 deg from point P w.r.t to -x axis.
Now their vertical component is in +y-direction, so both component will be added, and one horizontal component is in +x direction and one in -x direction, so they will cancel out.
So resultant electric field will be in +y direction.
Correct option is A.
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