Find the electric potential at p a. +0.36 N b. +5.3 times 10^4 N/C c. +7.9 times

Question

Find the electric potential at p a. +0.36 N b. +5.3 times 10^4 N/C c. +7.9 times 10^4 volt d. -7.9 times 10^1 volt e. -1.3 times 10^4 volt There are two resistors with R_A bigger than R_S and they are connected in parallel with a battery. a. There is more potential difference across R_A b. There is more potential difference across R_B c. There is the same current through each resistor d. There is the same potential difference across both resistors. Assume that a uniform magnetic field is directed into this page. If a proton is released with an initial velocity directed from the top edge to the bottom edge of the page, which of the following describes the direction of the resultant force acting on the electron? a. out of the page b. to the right c. to the left d. into the page Consider the circuit shown in the figure. What power is dissipated by the entire resistor circuit? Assume each resistor is 100 ohm and the current I is 0.97 A a. 140 W b. 28 W C. 56 W d. 112 W Two point charges are separated by 20 cm and have charges of +2.0 and -2.0 microcoulomb, respectively. What is the electric field at a point midway between the two charges? a. 28.8 times 10^6 N/C b. 14.4 times 10^6 N/C c. 36 times 10^5 N/C d. zero An ac series circuit with an rms current of 14.1 A will have what peak current? a. 28.2 A b. 14.1 A c. 7.1 A d. 20.0 A

Explanation / Answer

12)

V = k*Q/r

= 9*10^9*(-40*10^-6)/6.8

= -5.3*10^4 V

There is no correct answer in the given options.

13) d) There is the same potential diffrence across both resistors.

14)

b) to the right (for protons)

c) to the left (for electrons)

15) a) 140 W

Req = 100 + 100*100/(100+100)

= 150 ohms

P = I^2*Req

= 0.97^2*150

= 140 W

16) c) 36*10^6 N/c

E = E1 + E2

= k*q1/(d/2)^2 + k*q2/(d/2)^2

= 4*k*q1/d^2 + 4*k*q2/d^2

= 8*k*q/d^2 (where q1 = q2 = q)

= 8*9*10^9*2*10^-6/0.2^2

= 36*10^5 N/c

17) d) 20 A

I_peak = sqrt(2)*Irms

= sqrt(2)*14.1

= 20 A

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