C Chegg Study Guided Sox Mj LUS Secure h edugen wileyplus.co m/edugen/student/ A

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C Chegg Study Guided Sox Mj LUS Secure h edugen wileyplus.co m/edugen/student/ Apps HP Connected Watch NHL Live Stre watch NBA Live Strea D X 2017-b R 20 Bianchi order Assignment Open Assignment FULL SCREEN PRINTER VERSION 4 BACK NEXT ASSIGNMENT RESOURCES Chapter 12, Problem 102 HW15 (BONUS). PHYS2001 Stuver Your answer is partially correct. Try again. Chapter 12 Problem 028 A steel bicycle wheel (without the rubber tire s rotating freely with an angular speed of 16.6 rads. The temperature of the wheel changes from -194 to 203 oc. 033 No net external torque acts on the wheel, and the mass of the spokes is negligible. What is the angular speed of the wheel at the higher temperature? Chapter 12 Problem 047 Number 13.95 er problem Units Trad/s T the tolerance is +/-2% 061 Chau er 12 Problem SHOW HINT E Chapter 12. Problem LINK TO SAMPLE PROBLEM 084 Chapter 12 Problem Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER Review Results by Study objective Copyright 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved. a 8:41 PM 4x 4/26/2017 Type here to search

Explanation / Answer

For thermal expansion consider the wheel as band of length
L = 2··r
Assuming constant expansion coefficient () its length changes to
L = L·(1 + ·T)
<=>
2··r = 2··r·(1 + ·T)
Hence the radius changes to:
r = r·(1 + ·T)
Moment of inertia of the hot wheel is:
J = m·r²
= m·r²·(1 + ·T)²
= J·(1 + ·T)²

Angular momentum of hot and cold wheel are equal
·J = ·J
hence:
= ·J/J
= / (1 + ·T)²
= 16.6rad/s / (1 + 1.2×10-6K^-1 · 397K)²
= 16.58 rad/s

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