An aluminum washer has an outer radius ro = 2.79 cm and an inner radius of ri =

Question

An aluminum washer has an outer radius ro = 2.79 cm and an inner radius of ri = 0.57 cm. The temperature of the washer is raised from 341 K to 779 K.

If the mass of the washer is 0.04 g, the molar mass of aluminum is 26.98 g/mol, and the molar specific heat of aluminum is 24.3 J/mol-K, what is the change in the internal energy of the washer?

If the coefficient of linear expansion of aluminum is 2.22 × 10-5 K-1, what is the change in the outer radius of the aluminum washer?

What is the change in the inner radius of the aluminum washer?

What is the change in area of the washer?

Explanation / Answer

1)Change in internal energy of washer

dU = n*c*dT
dU = (0.04/26.98)*24.3*(779-341) = 15.779 J

(2) Cahne in the outer radius
dL = a*ro*dT
dL = 2.22 × 10-5 x 2.79 x (779-341) = 0.0271 cm

(3) change in the inner radius
dL = a*ri*dT
dL = 2.22 × 10-5 x 0.57 x (779-341) = 0.00554 cm

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