In the graph below, each unit on the horizontal axis is 4.0 m3 and each unit on
ID: 1614640 • Letter: I
Question
In the graph below, each unit on the horizontal axis is 4.0 m3 and each unit on the vertical axis is 5.0 atm.
(a) A gas is compressed along the path AC. What is the work done on the gas in this case?
How is the work done related to the area under the curve? What is the difference between work done by the gas and on the gas? J
(b) If the gas is instead compressed along the path ABC, what is the work done on the gas?
What is the work done along the path where the volume is constant? J
(c) What is the work done on the gas if the path of compression is along ADC?
What is the work done along the path where the volume is constant? J
A DExplanation / Answer
(a)
work = area under graph AC
work = ((2*5*10^5)*(4*4) )+((1/2)*4*4*7*5*10^5)
Work = 44*10^6 J
work done by gas is positive
work done by gas negative
(b)
work area under ABC
W = WAB + WBC
W = 0 + (9*5*10^5*4*4) = 72*10^6 J
work done along the path where the volume is constant WAB = 0
(c)
work area under ADC
W = WAD + WDC
W = (2*5*10^5*4*4) + 0 = 16*10^6 J
work done along the path where the volume is constant WDc = 0
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