A 195 g block is launched by compressing a spring of constant k=200N/m a distanc

Question

A 195 g block is launched by compressing a spring of constant k=200N/m a distance of 15 cm. The spring is mounted horizontally, and the surface directly under it is frictionless. But beyond the equilibrium position of the spring end, the surface has coefficient of friction =0.27. This frictional surface extends 85 cm, followed by a frictionless curved rise, as shown in the figure.(Figure 1)

Part A

After launch, where does the block finally come to rest? Measure from the left end of the frictional zone.

Explanation / Answer

here,

mass , m = 0.195 kg

K = 200 N/m

distance , x = 0.15 m

u = 0.27

A)

the potential energy gained = initial potnetial energy stored in spring - work done by friction

m * g * h = 0.5 * k * x^2 - u * m * g * x

0.195 * 9.81 * h = 0.5 * 200 * 0.15^2 - 0.27 * 0.195 * 9.81 * 0.15

solving for h

h = 1.14 m

the height achived is 1.14 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.