R_1 = 2.5 ohm; R_2 = 3.5 ohm; R_3 = 8.0 ohm; R_4 = 8.0 ohm; R_5 = 5.0 ohm; a. If
ID: 1615204 • Letter: R
Question
R_1 = 2.5 ohm; R_2 = 3.5 ohm; R_3 = 8.0 ohm; R_4 = 8.0 ohm; R_5 = 5.0 ohm; a. If V = 36.0 V, FIND; 1.Equivaleny resistance; 2. The current in each resistor and voltage across each resistor. b. What is the charge on each capacitor? What is the voltage across each capacitor'? C_1= 3.0 mu F; C_2 = 1.5 mu F; C_3 = 2.0 mu F; C_4 = 6.0 mu F; C_5 = 10 mu F; V = 2.0 V A. Use a 200 loops coil as a primary to build a transformer for powering your device with the 9.0 V and not to exceed 3.0 X of current, while the primary coil is attached to V = 110.0. 1. How many lopes should me in secondary coil? 2. What fuse(I_1 = ?) should you put in the primary circuit assume 100 % efficiency? 1. As actual efficient is 80%, what maximum current would be in the primary coil? b. A coil of wire with 550 turns and a diameter of 2.50 cm is placed in a uniform magnetic field where B = 420 m T. During a time of 15.0 ms the coil is rotated so the normal and B are perpendicular, and an average EMF induced in the coil was 2.8 V. What angle relative to B had the normal (N) to the plane of the coil at the beginning a. The generator is supplying 110 V AC at frequency 1=50 Hz.; R=200.0 ohm; C =6 mu F; L = 0.4H. 1. What is the current in the circuit? 2. Find the resonant frequency 3. Find the voltage drop in each element b. The generator is supplying 110 V AC at frequency f = 50 Hz.; R = 200.0 ohm; C =6 mu F; L = 0.4H. You need to adjust the circuit so f = 50 Hz would become the resonant frequency. Do it by replacing: 1. The capacitor to another capacitor. What is its capacitance? 2. The inductor to another one. What is its inductance? A. When light comes from an unknown liquid to the Air it has a critical angle of 47 degree. Find 1. the critical angle when the Glass is surrounded by this liquid if the same Glass has a critical angle of 41 degree when it is surrounded by Air (n_air = 1.00); 2. The index of refraction of the Glass; 3. The Index of refraction of the liquid. To measure the distance to an object you created its image on the screen by placing a lens at 12 cm distance in As you were not sure about the focal length of that lens, you moved it 5 cm towards the object and you had to move the from the lens on another 5 cm 1. S_0 = ? 2. F = ? A. A 3.0 cm high object is located 15.0 cm front of a converging lens of focal length 10.0 cm. A second length +24.0 cm is located 6.0 cm beyond the first lens. Find the final image position, size and natural (real, virtual). b. A single slit of width 0.20 mm is illuminated by light, lambda = 550 nm. Find the width of diffraction maximum when viewed at a distance of 5.0 m from the slit.Explanation / Answer
3B.
EMF = -N*d(phi)/dt
phi = B.A = B*A*cos theta
EMF = -N*B*dA*cos theta/dt
cos theta = EMF*dt/(N*B*dA)
theta = arccos (2.8*15*10^-3/(550*420*10^-3*pi*0.0125^2))
theta = 68.26 deg
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