Consult Interactive solution 21.23 to review a model for solving this problem. A

Question

Consult Interactive solution 21.23 to review a model for solving this problem. A proton with a speed of 3.38 times 10^6 m/s is shot into a region between two plates separated by a distance of 0.27 m. As the that are drawing shows, a magnetic field exists between the plates, and it is perpendicular to the velocity of the proton. What must be the magnitude of the magnetic field so the proton just misses colliding with the opposite plate? T A horizontal wire of length 0.51 m, carrying a current of 8.1 A, is placed in a uniform external magnetic field. When the wire is horizontal it experiences no magnetic force. When the wire is tilted upward at an angle of 19 degree experiences a magnetic it force of 4.70 times 10^-3 N. Determine the magnitude of the external magnetic field.

Explanation / Answer

Here

Using

F = qvB = mv^2/r

Now r should be equal to the distance between the plates

Sp

B = mv/qr = 1.67*10^-27*3.38*10^6/1.602*10^-19*0.27 = 0.1305 T

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