Find the force (both magnitude and direction) on electric charge q_3 in the diag

Question

Find the force (both magnitude and direction) on electric charge q_3 in the diagram below. The distance separating charges q_1 and q_2 is 13.00 cm. The distance d is 1.5 m. The charge are: q_1 = -8.0 times 10^-7 C, q_2 = -8.0 times 10^-7 C and q_3 = 2.5 times 10^-7 C. A charge q_1 = -9.75 mu C is at the origin, while a second charge q_2 = -6.50 mu C is located point y-axis at the point y = 12.0 cm. At what point on the y-axis is the electric field (E) equal to zero? Electric charges of 1.00 mu C, -3.00 mu C, -5.00 mu C and 7.00 mu C are placed on the corners of a rectangle with sides having lengths of 30.0 cm and 46.0 cm. Find the electric potential (V) at the center of the rectangle. Find: the equivalent resistance (R) of the series circuit in the diagram below if R_1 = 9.0 ohms, R_2 = 17.0 ohms and R_3 = 29.7 ohms and find the electric current through each of those resistors. the equivalent resistance (R) of the parallel circuit in the diagram below if R_1 = 6.0 ohms, R_2 = 11.0 ohms and R_3 = 4.8 ohms and find the electric current through each of those resistors.

Explanation / Answer

Part a)-

As we can see that R1,R2 and R3 are in series then -

Req = R1+R2+R3

= 9 +17 + 29.7

= 55.7 ohm

i = V/R

=14/55.7 = 0.251A (The current will be same in allthe resistance in case of series connection)

Part b)-

Req = R1 || R2 || R3

= (R1R2 + R2R3 + R1R3) / R1R2R3

=(66 + 52.8 + 28.8)/ 316.8

= 0.47 ohm

i =V/R

= 14/0.47

=29.79A

Thank you !!! Have fun

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