Read Study&Practice; Assignment open Assignment er Practice Chapter 29, Problem

Question

Read Study&Practice; Assignment open Assignment er Practice Chapter 29, Problem 55 A long solenoid with 8.14 turns/cm and a radius of 8.72 cm carries a current of 15.4 mA. A current of 6.25 A Chapter Problemu exists in a straight conductor located along the central axis of the solenoid. (a) At what radial distance from the axis in centimeters will the direction of the resulting magnetic field be at 52.4° to the axial direction? (b) What is the magnitude of the magnetic field there? Problem (a) Number units (b) Number r units Chapter Problem 53 Click if you would like to Show Work for this question: objective By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: Unlimited SAVE SLEMITANSRERI 2000-2017 by John Wiley & Sons, Inc. or related companies. Al rights reserved.

Explanation / Answer

(a)
Due to the solenoid, magnetic field is in the axial direction. Its magnitude is independent of axial distance, and is given by
B1 = 0 * no. of turns per unit length * current = 4*PI E-7*814*0.0154 = 157.5*E-7 T
This is in the x-direction.

Due to current carrying conductor, the field is circular, and the direction is given by right hand thumb rule. If the current is flowing towards right, then at points just behind the conductor, the field is upwards. Magnitude is given by
B2 = 0 * current / (2**r)
This is in the y-direction.

Now find the angle of the resultant force:
tan(52.4 degrees) = B2/B1=1.299 => B2 = 204.5*E-7 T
Solve for r!

r = 0 * current / (2**B2) = (4*PI E-7*6.25) / (2*PI*204.5*E-7) = 0.0611 m = 6.11 cm

(b)
Resultant magnetic field
B = sqrt(B1^2+B2^2) = 2.58*10^-5 T

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.