Show much pressure needed to compress the volume of an iron block by 0.10%? Expr

Question

Show much pressure needed to compress the volume of an iron block by 0.10%? Express the answer in N/m^2. The compressive strength is 55 times 10^6N/m^2. A bottle has a mass of 35.00g when empty and 98.44g when filled with water. When filled with another fluid, the mass is 89.22g. What is the specific gravity of this other fluid? What fraction of a piece of iron will be submerged when it floats in mercury? (density of iron 7.8g times 10^3kg/m^3. Density of mercury is 13.6 times 10^3kg/m^3). If a wave travels with the speed 340m/s, and the frequency of it is 100/s, what is the wavelength of the wave?

Explanation / Answer

P = B ( deltaV / V )

P = (55 x 10^6) (0.10/100)

P = 55 x 10^3 Pa .........Ans

4. M_water = 98.44 - 35 = 63.44 g

Volume = 63.44 cm^3

Mass of fluid = 89.22 - 35 = 54.22 g

specific gravity = 54.22 / 63.44

= 0.855

5. Weight = V rho_iron g

Fb = V_submergd rho_mercury g

To float, W - Fb = 0

V rho_iron g - V_submergd rho_mercury g = 0

Vsubmbergdd / V = 7.8 / 13.6

= 0.57

6. v = 340 m/s

f = 100 Hz

lamdba = v / f

= 3.4 m

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