RB = 15.6 Ohms, RC = 990 Ohms, RD= 99.7 Ohms, how do i calculate RA given these

Question

RB = 15.6 Ohms, RC = 990 Ohms, RD= 99.7 Ohms, how do i calculate RA given these values?

The expected RA should be about 147.9 so the calculated value should be relatively near this value.

Wheatstone Bridge neatstone Bridge offers an interesting application of Kir ts of four resistors arranged on two branches which ar probe (as seen in Figure 5 As you will derive in t mathematic relationship between the resistances wi e drop across the branches when hooked up to a bat wariable resistor to adjust one of the resistances in oro voltage across the branches, at which point y ich was is satisfied. One can exploit this to otherwise and that by calculating i mathematical relationship. figure 5: Wheatstone Bridge circuit. 1002, and a 10000 resistor. Measure each a 99

Explanation / Answer

when the wheatstone bridge is balanced

RA/RB = Rc/RD

RA/15.6 = 990/99.7

RA = 155 ohms <<------answer

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