011 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with
ID: 1618073 • Letter: 0
Question
011 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with focal length 5.5 m Another convex lens is placed 8.58 m behind the first lens with a focal length 3.4 m (see the figure below). Note: Make a ray diagram sketch in order to check your numerical answer 5.5 m 3.4 m P1 8.58 m 10 m 10 15 20 At what distance is the first image from the first lens? Answer in units of m. 012 (part 2 of 4) 10.0 points What is the magnification of the first image? 013 (part 3 of 4) 10.0 points At what distance is the second image from the second lens? Answer in units of m. 014 (part 4 of 4) 10.0 points What is the magnification of the final image, when compared to the initial object?Explanation / Answer
011 )
do = object distance = 10 m
f = focal length = 5.5 m
di = image distance
using the lens equation
1/do + 1/di = 1/f
1/10 + 1/di = 1/5.5
di = 12.22 m
012)
magnification is given as
m = - di/do = - (12.22)/10 = - 1.22
013)
do2 = object distance = 12.22 - 8.58 = 3.64
di2 =image distance ?
f2 = focal length = 3.4 m
using the lens equation
1/do2 + 1/di2 = 1/f2
1/3.64 + 1/di2 = 1/3.4
di2 = 51.6 m
014)
m2 = magnification by second lens = - di2 /do2 = - 51.6/3.64 = - 14.2
total magnification is given as
m = m1 m2 = (-1.22) (-14.2) = 17.32
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