iPad F 8:25 PM edugen wileyplus com Go Cutnell, Physics, 10e GENERAL PHYSICS (PH
ID: 1618601 • Letter: I
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iPad F 8:25 PM edugen wileyplus com Go Cutnell, Physics, 10e GENERAL PHYSICS (PHY 130-140) Study & Practice Assignment ORION Open Assignment ESOURCES Chapter 29, Problem 11 work 23. When light with a wavelength of 227 nm is incident on a certain metal surface, electrons are ejected with a maximum kinetic energy of 3.so x 10-19 J. Determine the wavelength (in nm) of light that should be used to double the maximum kinetic energy of the electrons ejected from this surface. Number Units Problem 1 Problem 26 Click if you would like to Show Work for this question Qpen Show Work by Study By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: o of 4 used SAVE FOR LATER SUSMITANSWER Eam Maximum Points available only if you answer this question correctly in four or less Copyright D 2000-2017 by John Wiley &Sons;, Inc. or related companies. All rights reserved ent I Privace Polo I 2.2000-2012 lohn Miley & Sons Inc. All Rights Reserved. A Division of lohn Miley Sons Inc. Version 4.22.3.4Explanation / Answer
he work function Wo is a property of the metal surface itself, so it remains the same for any wavelength of incident light.
Wo = -KEmax + hc/lambda
Wo = -KEmax2 + hc/lambda2= -KEmax1 + hc/lambd1
KEmax2 - KEmax + kc/lambd1 = hc/lambda2
KEmax2 = 2KEmax1
lambda2 = 1/[KEmax1/hc + 1/lambda1]
KEmax1 = 3.5 x 10^-19 J
lambda 1 = 227 nm = 227 x 10^-9 m
h = planck constant
c = speed of light
lambda2 = 1.5912 x 10^-7 m
lambda2 = 159.12 nm
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