31% iPad 8:25 PM edugen wiley plus.com Practice Assignment assignment FULL scREE

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31% iPad 8:25 PM edugen wiley plus.com Practice Assignment assignment FULL scREEN PRINTER VERSION .BACK NEXT CES Chapter 29, Problem 26 What is (a) the wavelength of a 5.90-ev photon and (b) the de Broglie wavelength of a 5.90-ev electron? (a) Number Units (b) Number Units Click if you would like to show Work for this question QRen Show Work 14 By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: o of 4 used SAVEFORLATER SUBMET ANSwER Earn Maximum Points available only if you answer this question correctly n four attempts or less 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved rivacy Polky I 2.2000-2012 lohn Sonsuns. All Rights Reserved. A Division of wilem s Sons Inc. 2ohn Version 4.22.3.4

Explanation / Answer

here,

a)

E = 5.9 eV

h * c/ lamda = 5.9 * 1.6 * 10^-19

6.634 * 10^-34 * 3 * 10^8 /( 5.9 * 1.6 * 10^-19 ) = lamda

lamda= 2.1 * 10^-7 m

b)

the Debroglie's wavelength , lamda = h/( m*v)

lamda =h/sqrt(2 * m * k)

lamda = 6.634 * 10^-34 /sqrt(2
* 9.1 * 10^-31 * 5.9 * 1.6 * 10^-19 )

lamda = 5.06 * 10^-10 m

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