Finish writing the complementary sequence: What is as an RNA: What is the probab
ID: 161907 • Letter: F
Question
Finish writing the complementary sequence: What is as an RNA: What is the probability that a random 4 nt sequence is GGGG? What is the probability that a random 4 nt sequence is GATC? Probability that a random 6 nt sequence is GGATCC? Consider a random 10,000 bp circular piece of DNA. How many GGGG sites are expected? (Consider both strands). Consider a random 10,000 bp circular piece of DNA. How many GATC sites are expected? (Tricky) Consider a random 10,000 bp circular piece of DNA. How many GGATCC sites are expected? Consider a random 10,000 bp circular piece of DNA. How many 8nt AGGATCCT sites are expected? How many different 30 nt RNA sequences are possible? On average, how many ways can a 10 amino acid peptide be encoded?Explanation / Answer
3) Four bases A, T, G and C
Probability of getting any base out of four bases = 1/4
Probability of G at position 1 is 1/4
Probability of G at position 2 is 1/4
Probability of G at position 3 is 1/4
Probability of G at position 4 is 1/4
So 1/4 x 1/4 x 1/4 x 1/4 = 3.9 x 10-3 or 0.39 %
Probability of getting GGGG is 3.9 x 10-3 or 0.39 %
4) Probability of getting GATC is also 3.9 x 10-3 or 0.39 %
5) Probability of getting GGATCC
There are six nucleotides so its probability is (1/4)6
Probability of getting GGATCC = 2.44 x 10-4 or 0.0244 %
6) Number of GGGG sites
In question 3 we have calculated the probability of getting GGGG is 3.9 x 10-3
Circular DNA with 10000 bp and if both strands are considered 20000 bp.
3.9 x 10-3 x 20000 = 78
Number of GGGG sites = 78
7) One strand is considered so 10000 bp
Probability of getting GATC is also 3.9 x 10-3
3.9 x 10-3 x 10000 = 39
Number of GATC sites = 39
8) Number of GGATCC sites
Probability of getting GGATCC = 2.44 x 10-4
2.44 x 10-4 x 10000 = 2.44 or 2 sites
9) Number of 8 nt sites
(1/4) 8 x 10000 = 0.152
10) 20 n where n is the length of peptide
20 10 = 1.024 x 1013 combinations
11) 4 n
4 30 = 1.15 x 10 18 combinations
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