#1. When the current through an inductor is decreasing at a rate of 0.18 A/s, th
ID: 1619576 • Letter: #
Question
#1. When the current through an inductor is decreasing at a rate of 0.18 A/s, the magnitude of the self-induced emf is 0.0250 V.
a. What is the inductance of the inductor?
b. Solenoid. 600 turns. What is the average magnetic flux through each turn when the current is 0.750 A?
#2. A series of RLC circuit contains a 4700 ohm resistor, 0.350mH inductor and 5microF capacitor connected accross the terminals of an AC generator. Frequency of a generator is 5KHZ and current(I rms) through circuit is 0.950A.
Find: Impedance(Z) of the circuit, Voltage(V rms) accross terminals of generator, resonant frequency,Wo(in rad/s), Phase angle between generator voltage and current through circuit, if generator frequency is changed so that the circuit is operating at resonance, what is the average power delivered to circuit by generator?
Thank you. Will thumbs up if you do both
Explanation / Answer
A.
we know that:
EMF = -L*di/dt
L = EMF*(dt/di)
L = 0.0250/0.18 = 0.139 H
B.
L = N*phi/i
emf = L*di/dt
emf = N*phi*(di/dt)/i
phi = EMF*i/(N*(di/dt))
Using the given values:
phi = 0.0250*0.750/(600*0.18)
Avg. magnetic flux = 1.74*10^-4 Wb
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