If the plates in No.10 are 1.00 cm. apart what is the strength of the electric f
ID: 1620058 • Letter: I
Question
Explanation / Answer
12 ) Q =c*v =100*10^-6*20=2*10^-3
13 ) flux = E X A= 10000*3*2*10^-4= 6 Nm^2/C
14 ) change in potential = (pe2-pe1)q =21.6-7.2/3.6= 4000
15) w = F* d= q*e* d=20*1*10^-5= 2*10^-4 J
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