If a force of 25 N is applied to an object over a parallel displacement of 20 m,

Question

If a force of 25 N is applied to an object over a parallel displacement of 20 m, how much work is done on the object by the applied force? 1.25 J 25 J 45 J 500 J If the object in question 1 moves at a constant velocity, how much net work is done on the object? 0 J 45 J 500 J There's not enough information. If an object is falling with some nonzero initial speed, and while we watch for some amount of time its kinetic energy increases by 200 J, what is the corresponding change in its potential energy? (Neglect air resistance.) 200 J 0 J -200 J There's not enough information. If the object in question 3 has a mass of 22 kg, how much did its velocity increase during the time we observed it? 4.26 m/s 9.09 m/s 18.18 m/s There's not enough information. A bat contacts a resting tee-ball that has a mass of 1.7 kg for 0.4 s, and the tee-ball leaves the tee with a Velocity of 15 m/s. How much force did the bat exert on the ball? 10.2 N 22.1 N 25.5 N 63.75 N If a 65 N force is applied to push an object across a table at a constant velocity, what is the magnitude of the friction force? Less than 65 N Exactly 65 N More than 65 N There's not enough information.

Explanation / Answer

1 ans

Given that

force F=25 n

length L=20 m

basing on the concept of work energy and power

now we find the work

work W=F*L=25*20=500 J

--------------------------------------------------------------------------------------------------------------

2 ans

if the object is moving constant velocity the work done by gravational is zero Wg=0

the net work done Wnet=Wg+Wf

=0+500=500 N

--------------------------------------------------------------------------------------------------------------------------------

3 ans

Given that

kinetic energy K.E=200 j

now we find the potential energy

K.E+P.E=constant

P.E=-K.E=-200 J

---------------------------------------------------------------------------------------------------------------------------------------

4 ans

Given that

mass m=22 kg

now we find the speed

speepV=[2*200/22]^1/2=4.26 m/s

-------------------------------------------------------------------------------------------------------------------------------------------

5 ans

given that

mass m=1.7 kg

time t=0.4 sec

velocity v=15 m/s

now we find the force

force F=1.7*15/0.4=63.75 N

the magnitude of frctiction is less than 65 N

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.