A conducting loop is formed by running a wire completely around the edge of this
ID: 1620335 • Letter: A
Question
A conducting loop is formed by running a wire completely around the edge of this page. A uniform magnetic field of 250 T directed out of the page is decreasing at the rate of 5.0 T/s. What is the direction of the current induced in the loop? A) The induced current will move clockwise around the edge of the page. B) The induced current will alternate between clockwise and counterclockwise. C) The induced current will move counterclockwise around the edge of the page. D) No current will be induced because the loop and field do not have the right orientation. A bar of copper (black bar at the right of the page) is moving from left to right across the page. If there is a magnetic field directed out of the page, which side of the bar has a positive charge? A) front B) bock C)) top D) bottom E) right F) left Who's Law governs the calculation of an induced EMF due to a changing magnetic field? A) Ampere B) Faraday C) Lenz D) Maxwell E) Ohm A wire runs along the left edge of this page. If the direction of the current in the wire is as indicated, what is the direction of the magnetic field with respect to the middle of the page (point A)? A) The field will go through point A from the left to the right across the page. B) The field will he directed into the page at point A. C) The field will go through point A from the bottom to top of the page D) The field will be directed out of the page al point A. E) The field will be directed diagonally through point A from the upper left to lower right of the page. Relative to the page what is the direction of the force on a negative charged particle moving down the page through a uniform magnetic field which is directed right to left across the page? A) right B) left C) up D) down E) into the page F) out of the pageExplanation / Answer
2.2
According to lenz's law, the magnetic flux due to induced current should be increase into the page.using ampere's right hand rule the induced current will move clockwise around the edge of the page.
so, option A is the answer.
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