In the figure, a block weighing 15.6 N, which can slide without friction on an i

Question

In the figure, a block weighing 15.6 N, which can slide without friction on an incline at angle theta = 45.0 degree, is connected to the top of the incline by a massless spring of unstretched length 0.570 m and spring constant 120 N/m. The block is initially at its equilibrium position. (a) How far from the top of the incline is the block's equilibrium point? (b) If the block is pulled slightly down the incline and released, what is the period of the resulting oscillations? (a) Number ____________ Units (b) Number ____________ Units

Explanation / Answer

a)

Force component along the inclined is

    k x = m g sin

       x = m g sin / k

           = 15.6 sin 45 / 120

           =0.0919 m

Hence distance from the top is 0.57 + 0.0749 = 0.6619m

b) The time period is given by

            T = 2 ( m / k )

               = 2 ( 15.6 / (9.8)(120)

                = 0.72367 sec

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.