What is created in pair production? a electron and an antiproton an electron and

Question

What is created in pair production? a electron and an antiproton an electron and a photon a proton and an electron a proton and an antiproton an electron and a positron What is the de Broglie wavelength of an electron whose kinetic energy is 1.0 eV? 1.2 nm 520 nm 52 nm 0.64 nm 8.2 nm If the momentum of an electron is 1.95 times 10^-27 kg.m/s, what is its de Broglie wavelength? 420 nm 340 nm 210 nm 520 nm 170 nm What is the momentum of a 600 nm photon? 2.07 N.s 2.07 kN.m 2.07 Kev/c 2.07 MeV/c 2.07 eV/c A person of mass 50 kg has a wavelength of 4.42 times 10^-36 m when running. How fast is she running? 3 m/s 5 m/s 1 m/s 2 m/s 4 m/s What is the de Broglie wavelength of a ball of mass 200 g moving with a speed of 30 m/s? 2.2 times 10^-31 m 6.67 times 10^-31 m 1.1 times 10^-34 m 6.67 times 10^-27 m 4.5 times 10^-28 An electron has a kinetic energy of 10 eV. What is the wavelength of this electron? 1.2 times 10^-10 m 1.9 times 10^6 m 3.9 times 10^-10 m 3.8 times 10^-6 m 5.9 times 10^6 m A hydrogen atom is in the 6h state. Which of the following could be an orbital quantum number? 6 8 5 9 7 A hydrogen atom is in the 6h state. Which one of the following is not a magnetic quantum number? 1 6 2 0 4

Explanation / Answer

48.

lambda = h/p

lambda = 6.626*10^-34/(1.95*10^-27)

lambda = 3.39*10^-7 m = 340 nm

Correct option is B.

49.

p = h/lambda

p = 6.626*10^-34/(600*10^-9) = 1.10*10^-27 kg-m/sec

p = 1.1*10^-27*3*10^8/(1.6*10^-19) eV/c

p = 2.0625 eV/c

Correct option is E.

50.

lambda = h/p = h/mv

v = 6.626*10^-34/(50*4.42*10^-36)

v= 2.99 m/sec

Correct option is A.

51.

lambda = 6.626*10^-34/(0.2*30)

= 1.1*10^-34 m

Correctoption is C.

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