The next three questions will revolve around a sequence of operations performed

Question

The next three questions will revolve around a sequence of operations performed on the electroscope, and you are to determine its final charged state. Before the start of each operation, the electroscope is returned to an uncharged state. A positively charged rod is placed in contact with the top knob of the electroscope and then removed. The electroscope's charge is (a) Positive (b) Neutral (c) Negative A positively charged rod is placed close to, but not touching, the top knob of the electroscope and then removed. The electroscope's charge is (a) Positive (b) Neutral (c) Negative A positively charged rod is placed close to, but not touching, the top knob of the electroscope. The holder of the rod then touches the stem of the electroscope with the finger. Finger is removed, and then the rod is pulled away. The electroscope's charge is (a) Positive (b) Neutral (c) Negative Its essential elements are two different metals, spatially separated and sometimes immersed in an acidic solution. This is (a) a resistor (b) a battery (c) a switch (d) a capacitor An electron-volt is a) the force acting on an electric in a field of 1 N/C b) the energy needed to move an electron through 1 meter in any electric field (c) the force required to move an electron 1 meter (d) the energy gained by an electron in moving through a potential difference of 1 volt

Explanation / Answer

7.

When the positively charged rod is put in contact with the electroscope, it would get positively charged.

So, correct option is (a)

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8.

When the charged rod is pulled away without making contact with the knob there would be no charge on the rod.

So, the correct option is, (b)

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9.

When the positively charged rod is brought near the knob of the electroscope, there will induced negative charge on the knob and equal positive charge will be accumulated elsewhere on the electroscope making it's charge neutral.

But when finger touches the stem, the positive charge of the electroscope will flow to the holder's body and after that when electroscope is removed, there will be net negative charge on the electroscope.

So, the correct option is (c).

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10.

This is the design of a battery.

So, the correct option is (b)

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11.

When a charge q is moved through a potential difference of V it gains energy equal to qV. So, when an electron moves through a potential difference of 1 V, it gains energy equal to 1 eV, where e is the charge on electron.

So, the correct option is (d)

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification, modification or correction, feel free to ask.....

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