Pad F 5 of 15 67% moodle telt unsw.edu. STANDING WAVES ON A STRING Answer the fo
ID: 1623529 • Letter: P
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Pad F 5 of 15 67% moodle telt unsw.edu. STANDING WAVES ON A STRING Answer the following in the spaces provided, showing all reasoning and working. Write down an expression for this sinusoidal wave travelling to the right, also write down an expression for the reflected wave travelling to the left. Derive the equation for the standing wave by adding the equations for the incident and reflected wave. Use this to find the maximum displacement at the crest and halfway between a node and an antinode. Compare this with your result from the diagram. You may find the following relationship useful: sin(A) t sin (B) 2sin (A/2 t B2) cost AV2 F B/2) A transverse sinusoidal progressive wave, wavelength 200mm, amplitude 20mm, and frequency 50 Hz, is reflected from the clamped end of a string. At timer 0 a point of maximum displacement of the incident wave is at the left hand side of the grid two pages over. The first grid, two pages over shows the displacement produced by: The incident wave, The reflected wave, and The resultant wave the wave resulting from the superposition of these) i.e. the stand- ing wave, at time 0. (At any particular point the resultant displacement is the sum of the displacements produced by each wave) (a) On the remaining grids, draw in The incident wave, The reflected wave use a different coloured pencil), and The wave resulting from their superposition (use a pencil of a third colour) FIRST YEAR Yslos LABORATORY MANuALExplanation / Answer
Q1. The equation for the sinusoidal wave travelling to the right = y= a sin (kx-wt)
where a= amplitude k= wave number and w= angular velocity
The equation for the reflecting sinusoidal wave travelling to the right = y= a sin (kx+wt)
when the incident wave and its reflecting waves superimpose together, the resultant is called as standing wave
so y= y1 + y2
= a sin (kx-wt) + a sin (kx +wt)
= 2a sin(kx) cos (wt)
At crest, maximum displacement = 2a
At node, displacement=0
At antinode, displacement= amplitude
all the best in the coursework
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